How do you factor completely: $8x^2 − 11x + 3$ ?

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Answer 1 · 2015-07-17T07:27:47

$= color(blue)((8x-3)(x-1)$

$8x^2−11x+3$

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like $ax^2 + bx + c$ , we need to think of 2 numbers such that:

$N_1*N_2 = a*c = 8*3 = 24$
and
$N_1 +N_2 = b = -11$

After trying out a few numbers we get:
$N_1 = -3$ and $N_2 =-8$

$(-3)*(-8) = 24$ and
$(-3)+(-8)=-11$

$8x^2−11x+3 = 8x^2−8x - 3x+3$

$8x(x-1) -3 (x-1)$

$= color(blue)((8x-3)(x-1)$

How do you factor completely: 8x^2 − 11x + 38x^2 − 11x + 3?