How do you factor completely $8x^2 – 32x + 24$ ?

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Answer 1 · 2016-05-14T16:48:37

$8x^2-32x+24=8(x-1)(x-3)$

$8x^2-32x+24=8(x^2-4x+3)$

$x^2-4x+3=(x-1)(x-3)$

$8x^2-32x+24=8(x-1)(x-3)$

How do you factor completely 8x^2 – 32x + 248x^2 – 32x + 24?