How do you factor completely $8x^3 + 10x^2 + 4x + 5$ ?

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Answer 1 · 2016-07-14T03:12:54

$(2x^2 + 1)(4x +5)$

Re write the expression in order to factor by grouping:
$f(x) = 8x^3 + 4x + 10x^2 + 5$
$f(x) = 4x(2x^2 + 1) + 5(2x^2 + 1) = (2x^2 + 1)(4x + 5)$

How do you factor completely 8x^3 + 10x^2 + 4x + 58x^3 + 10x^2 + 4x + 5?