How do you factor completely $8 x^{3} - 20 x^{2} + 6 x - 15$ $8x^3-20x^2+6x-15$ ?

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How do you factor completely $8 x^{3} - 20 x^{2} + 6 x - 15$ $8x^3-20x^2+6x-15$ ?

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Answer 1 · 2018-06-24T20:53:31

$f (x) = (4 x^{2} + 3) (2 x - 5)$ $f(x) = (4x^2 + 3)(2x - 5)$

Explanation:

Factor by grouping:
$f (x) = 8 x^{3} - 20 x^{2} + 6 x - 15$ $f(x) = 8x^3 - 20x^2 + 6x - 15$
$f (x) = 8 x^{3} + 6 x - 20 x^{2} - 15$ $f(x) = 8x^3 + 6x - 20x^2 - 15$
$f (x) = 2 x (4 x^{2} + 3) - 5 (4 x^{2} + 3)$ $f(x) = 2x(4x^2 + 3) - 5(4x^2 + 3)$
$f (x) = (4 x^{2} + 3) (2 x - 5)$ $f(x) = (4x^2 + 3)(2x - 5)$

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How do you factor completely $8 x^{3} - 20 x^{2} + 6 x - 15$ $8x^3-20x^2+6x-15$ ?

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How do you factor completely $8 x^{3} - 20 x^{2} + 6 x - 15$ $8x^3-20x^2+6x-15$ ?