Question

How do you factor completely `96x^2 - 6y^2`?

Answer 1

`6(4x+y)(4x-y)`

Explanation:

Expression `= 96x^2-6y^2`

Notice that `6` is a factor of both terms.

So, Expression `= 6(16x^2-y^2)`

Then notice that `(16x^2-y^2)` is the difference of the two squares: `(4x)^2 and y^2`

Using the common identity: `a^2-b^2 = (a+b)(a-b)`

Expression `= 6(4x+y)(4x-y)`