How do you factor completely $96x^2 - 6y^2$ ?

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Answer 1 · 2018-05-18T02:29:07

$6(4x+y)(4x-y)$

Expression $= 96x^2-6y^2$

Notice that $6$ is a factor of both terms.

So, Expression $= 6(16x^2-y^2)$

Then notice that $(16x^2-y^2)$ is the difference of the two squares: $(4x)^2 and y^2$

Using the common identity: $a^2-b^2 = (a+b)(a-b)$

Expression $= 6(4x+y)(4x-y)$

How do you factor completely 96x^2 - 6y^2 96x^2 - 6y^2 ?