How do you factor completely #96x^2 - 6y^2 #?

1 Answer
May 18, 2018

Answer:

#6(4x+y)(4x-y)#

Explanation:

Expression #= 96x^2-6y^2#

Notice that #6# is a factor of both terms.

So, Expression #= 6(16x^2-y^2)#

Then notice that #(16x^2-y^2)# is the difference of the two squares: #(4x)^2 and y^2#

Using the common identity: #a^2-b^2 = (a+b)(a-b)#

Expression #= 6(4x+y)(4x-y)#