Question

How do you factor completely: `9x^2 + 25x -6`?

Answer 1

I found: `(x+3)(9x-2)`

Explanation:

What I did was to solve using the Quadratic Formula the second degree equation:
`9x^2+25x-6=0`
so: `x_(1,2)=(-25+-sqrt(841))/18` that gives you:
`x_1=-3`
`x_2=2/9`
So basically my equation can be written as:
`(x+3)(x-2/9)=0` or
`(x+3)((9x-2)/9)=0`
`(x+3)(9x-2)=0*9=0`

Answer 2

Factor: `y = 9x^2 + 25x - 6`

y = (9x + 2)( x - 3)

Explanation:

`y = 9x^2 - 25x - 6 =` a(x - p)(x - q)
I use the new AC Method to factor trinomials. (Google , Yahoo Search)
Converted `y' = x^2 - 25x - 54 =` (x - p')(x - q'). p' and q' have opposite signs. Factor pairs of (-54) --> (-1, 54)(-2, 27). This sum is 25 = -b. Then p' = 2 and q' = -27
`p = 2/9` and `q = -27/9 = - 3`

Factor form: `y = 9(x + 2/9)(x - 3) = (9x + 2)(x - 3)`