How do you factor completely: $9xy + 36x − 10y − 40$ ?

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Answer 1 · 2015-07-12T04:36:07

$9xy+36x-10y-40=(9x-10)(y+4)$

$9xy+36x-10y-40$

Factor by grouping.

$(9xy+36x)-(10y+40)$

Factor out the GCF for the first group and for the second group.

$9x(y+4)-10(y+4)$

Factor out the $(y+4)$ .

$(9x-10)(y+4)$

How do you factor completely: 9xy + 36x − 10y − 409xy + 36x − 10y − 40?