How do you factor completely $a^2 + 2ac - ab - bc + c^2$ ?

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Answer 1 · 2016-08-28T19:45:31

$a^2+2ac-ab-bc+c^2=(a+c-b)(a+c)$

$a^2+2ac-ab-bc+c^2$

$=(a^2+2ac+c^2)-(ab+bc)$

$=(a+c)^2-b(a+c)$

$=((a+c)-b)(a+c)$

$=(a+c-b)(a+c)$

How do you factor completely a^2 + 2ac - ab - bc + c^2a^2 + 2ac - ab - bc + c^2?