How do you factor completely $a^{2} - a b - a + b$ $a^2 - ab - a + b$ ?

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Answer 1 · 2016-04-06T12:56:49

$= (a - 1) (a - b)$ $=color(green)( (a -1 ) ( a -b)$

$a^{2} - a b - a + b$ $a^2 - ab - a + b$

Factorising by grouping:

We can factor this expression by making groups of two terms:
$(a^{2} - a b) + (- a + b)$ $(a^2 - ab) + ( - a + b)$

$a$ $a$ is common to both the terms in the first group, and $- 1$ $-1$ is common to both the terms in the second group:

$= a (a - b) - 1 (a - b)$ $= a( a -b) - 1(a-b)$
$a - b$ $a-b$ is common to both the terms now:

$= (a - 1) (a - b)$ $=color(green)( (a -1 ) ( a -b)$

How do you factor completely a2−ab−a+ba^2 - ab - a + b?