How do you factor completely a^4-b^4 ?

1 Answer
Apr 19, 2016

=(a^2+b^2)(a+b)(a-b)

Explanation:

In algebra, there is a formula known as the Difference of two squares: (a^2-b^2)=(a+b)(a-b)

In the case of a^4-b^4, you'll see that a^4 is just (a^2)^2 and b^4 is just (b^2)^2:
a^4-b^4=(a^2)^2-(b^2)^2
=(a^2+b^2)(a^2-b^2)
But as you can see, we can use the formula again:
=(a^2+b^2)(a+b)(a-b)
And this is the final answer