# How do you factor completely: b^2 -7b -44?

Jul 18, 2015

I found:
$\left(b - 11\right) \left(b + 4\right)$

#### Explanation:

I would first try to solve the equation:
${b}^{2} - 7 b - 44 = 0$ using the Quadratic Formula:
${b}_{1 , 2} = \frac{7 \pm \sqrt{49 + 176}}{2} = \frac{7 \pm 15}{2} =$
${b}_{1} = \frac{7 + 15}{2} = 11$
${b}_{2} = \frac{7 - 15}{2} = - 4$

So we can use these two results (with opposite signs) and get:
$\left(b - 11\right) \left(b + 4\right) = {b}^{2} - 7 b - 44$