How do you factor completely: #x^2 + 10x + 25#?

1 Answer
Apr 2, 2018

Answer:

#(x + 5)^2#

Explanation:

#ax^2 + bx + c#

Start by writing down all of the factors of c (25 in this case)
#25 = 1*25; 25 = 5*5#
now check, which of them might add up to, or have a difference of b (10 in this case)
# 5+5 = 10 #
so now we can insert these into the brackets:
#(x+5)(x+5)#
which is equivalent to #(x+5)^2#