# How do you factor completely x^2 - 12x + 20?

${x}^{2} - 12 x + 20 = \left(x - 2\right) \left(x - 10\right)$
${x}^{2} - 12 x + 20$
Find two numbers that when added equal $- 12$ and when multiplied equal $20$. The numbers $- 10$ and $- 2$ meet the criteria.
$\left(x - 2\right) \left(x - 10\right)$