How do you factor completely #x^2 + 12xy + 35y^2#?

Question

2768 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-25T11:10:51

#x^2 + 12xy+35y^2#
#=x^2+2.x.6y+35y^2#
#=x^2+2.x.6y+(6y)^2-y^2#
#= (x+6y)^2-y^2#
#= (x+6y+y)*(x+6y-y)#
#=(x+7y)(x+5y)#