How do you factor completely $x^2-14x+49$ ?

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Answer 1 · 2016-12-19T08:05:16

$(x-7)(x-7) = (x-7)^2$

All the information you need is in the quadratic trinomial ... Read from right to left:

Find factors of 49 which ADD (+) to give 14.

These will be $7 and 7$ because:
$7 xx 7 = 49 and 7+7 = 14$

The + sign shows that the signs in the brackets will be the SAME, the minus (-) shows that they will be negative:

$(x-7)(x-7) = (x-7)^2$

How do you factor completely x^2-14x+49x^2-14x+49?