# How do you factor completely x^2-14x+49?

Dec 19, 2016

$\left(x - 7\right) \left(x - 7\right) = {\left(x - 7\right)}^{2}$

#### Explanation:

All the information you need is in the quadratic trinomial ... Read from right to left:

Find factors of 49 which ADD (+) to give 14.

These will be $7 \mathmr{and} 7$ because:
$7 \times 7 = 49 \mathmr{and} 7 + 7 = 14$

The + sign shows that the signs in the brackets will be the SAME, the minus (-) shows that they will be negative:

$\left(x - 7\right) \left(x - 7\right) = {\left(x - 7\right)}^{2}$