# How do you factor completely x^(2/3)+5x^(1/3)-36?

Apr 19, 2016

I got: $\left(\sqrt[3]{x} + 9\right) \left(\sqrt[3]{x} - 4\right)$

#### Explanation:

We can try writing the fractional exponent as a root:
$\sqrt[3]{{x}^{2}} + 5 \sqrt[3]{x} - 36$
set $\sqrt[3]{x} = s$
we get:
${s}^{2} + 5 s - 36 = \left(s + 9\right) \left(s - 4\right)$

or: $\left(\sqrt[3]{x} + 9\right) \left(\sqrt[3]{x} - 4\right)$