Question

How do you factor completely `x^(2/3)+5x^(1/3)-36`?

Answer 1

I got: `(root3(x)+9)(root3(x)-4)`

Explanation:

We can try writing the fractional exponent as a root:
`root3(x^2)+5root3(x)-36`
set `root3(x)=s`
we get:
`s^2+5s-36=(s+9)(s-4)`

or: `(root3(x)+9)(root3(x)-4)`