How do you factor completely $x^2– 7x + 18$ ?

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Answer 1 · 2016-09-19T09:06:04

The given expression does not factor. Maybe these were meant?
$x^2 -7x -18 = (x+9)(x-2)$
$x^2 -9x +18 = (x-3)(x-6)$

This expression does not factor- there might be a typo perhaps?

The following are possibly what was meant?

$x^2 -7x -18 = (x-9)(x+2)$
Factors of 18 which subtract to make 7, are 9 and 2.

OR

$x^2 -9x +18 = (x-3)(x-6)$
Factors of 18 which ADD to give 9 are 6 and 3

Hope this helps.

How do you factor completely x^2– 7x + 18x^2– 7x + 18?