Question

How do you factor completely `x^3-x^2-x+1`?

Answer 1

Factor `f(x) = x^3 - x^2 - x + 1`

Explanation:

Since (a + b + c + d = 0), one factor is: (x - 1)

`y = (x - 1)(x^2 - 1) = (x - 1)^2(x + 1)`

ChecK: `f(x) = x^3 - x - x^2 + 1`. OK