How do you factor completely x^3-x^2-x+xx3x2x+x?

2 Answers
Jul 19, 2018

x^2(x-1)x2(x1)

Explanation:

First, we see that there's a factor of xx we can easily cancel:
x^3 - x^2 - x + x = x^3 - x^2 x3x2x+x=x3x2

From there, we can also factor out x^2x2:
x^3 - x^2 = x^2(x-1) x3x2=x2(x1)

Since each of these is fully factored, we are done.

Jul 19, 2018

x^2(x-1)x2(x1)

Explanation:

This expression can be simplified to

x^3-x^2x3x2

From here, we notice that both terms have an x^2x2 in common, which we can factor out. At this point, we are essentially dividing.

We get

x^2(x-1)x2(x1)

Hope this helps!