How do you factor completely: #y² - 12y + 32#?
because the middle sign is a minus
and the last sign is an addition, both the signs in the parenthesis would be minuses
now the two "
will be a pair of factors of
and add up to
so let's list the pairs of factors of
so it looks like the factor pair of
we would just substitute the two numbers in for the two "
Solve f(y) = y^2 - 12y + 32
Ans: (y - 4)(y - 8)
Find 2 numbers p and q knowing sum (-12) and product (32).
p and q have same sign, since a and c same sign.
Factor pairs of 32 --> (2, 16)(4, 8). This sum is 12 = - b.
Then, p = -4 and q = -8 (their sum must be -12, and not 12)
f(y) = (y - 4)(y - 8)