# How do you factor d²-8d+15?

Nov 24, 2015

${d}^{2} - 8 d + 15 = \left(d - 3\right) \left(d - 5\right)$
${d}^{2} - 8 d + 15$
Find two numbers that when added equal $- 8$ and when multiplied equal $15$. The numbers $- 3$ and $- 5$ meet the criteria.
$\left(d - 3\right) \left(d - 5\right)$