How do you factor #f(x)=x^2+8x+16#?

1 Answer
Jun 27, 2018

Answer:

#(x+4)^2#

Explanation:

We need a pair of numbers that add to make #8# and multiply to make #16#:

List the factors of #16#:

#16 and 1#

#rArr 16+1=17#

#8 and 2# 

#rArr 8+2=10#

#4 and 4#

#rArr 4+4=8#

#therefore# we place these in brackets:

#rArr (x+4)(x+4)#

Which can be written as:

#(x+4)^2#