Question

How do you factor `g(x)=x^3-x^2-x+1`?

Answer 1

Have a look:

Explanation:

You can collect `x` from the first and third term and `-1` from the second and fourth:
`g(x)=x(x^2-1)-1((x^2-1)` collect `(x^2-1)`:
`g(x)=(x^2-1)(x-1)=(x+1)(x-1)(x-1)`