How do you factor $g(x)=x^3-x^2-x+1$ ?

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Answer 1 · 2018-03-16T01:39:39

$color(green)(g(x) = (x + 1) * (x- 1)^2$

$g(x) = x^3 - x^2 - x + 1$

$g(x) = x^2 (x - 1) - 1 (x-1)$ Taking common $x^2$ out.

$=> (x^2 - 1) * (x - 1)$ Separating common terms.

As per identity, $(x + 1) * (x - 1) = x^2 - 1$

Hence $g(x) => (x + 1) (x - 1) (x - 1)$

$color(green)(g(x) = (x + 1) * (x- 1)^2$

How do you factor g(x)=x^3-x^2-x+1g(x)=x^3-x^2-x+1?