Question

How do you factor `k^3 - 2k^2r - 3kr^2`?

Answer 1

`k^3-2k^2r-3kr^2=k(k-3r)(k+r)`

Explanation:

`k^3-2k^2r-3kr^2`

`=k(k^2-2kr-3r^2)`

`=k(k-3r)(k+r)`