How do you factor $m^2+6m-27=0$ ?

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Answer 1 · 2015-09-20T16:45:28

$color(blue)((m-3)(m+9)$ is the factorised form of the expression.

$m^2 +6m -27=0$

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like $am^2 + bm + c$ , we need to think of 2 numbers such that:

$N_1*N_2 = a*c = 1 * -27 = -27$

AND

$N_1 +N_2 = b = 6$

After trying out a few numbers we get $N_1 = -3$ and $N_2 =9$
$(9)*(-3) =-27$ and $9+(-3)= 6$

$m^2 +6m -27=m^2 -3m +9m-27$

$=m(m-3) +9(m-3)$

$color(blue)((m-3)(m+9)$ is the factorised form of the expression.

How do you factor m^2+6m-27=0m^2+6m-27=0?