How do you factor #m^3 + 64n^3#?
This type of expression is known as the 'sum of two cubes', because both of the terms are perfect cubes.
Note the form of the factoring:
Following the method shown we will have:
To factor the sum or difference of two cubes:
This is how it is done:
Make Two brackets,
The first is found from the cube root of each term.
The second bracket is formed from the first to get three terms:
- square the first term
- change the sign
- multiply the two terms together
- square the second term