How do you factor m² + 4mn - 5n²?
1 Answer
Apr 16, 2018
Explanation:
"the factors of - 5 which sum to + 4 are + 5 and - 1"
rArrm^2+4mn-5n^2=(m+5n)(m-n)
"the factors of - 5 which sum to + 4 are + 5 and - 1"
rArrm^2+4mn-5n^2=(m+5n)(m-n)