How do you factor n - n^5n−n5? Algebra Polynomials and Factoring Factoring Completely 1 Answer Konstantinos Michailidis Mar 19, 2016 We have that n-n^5=n*(1-(n^2)^2)=n*(1-n^2)*(1+n^2)=n*(1-n)*(1+n)*(1+n^2)n−n5=n⋅(1−(n2)2)=n⋅(1−n2)⋅(1+n2)=n⋅(1−n)⋅(1+n)⋅(1+n2) Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x^2-82x2−8? Which method do you use to factor 3x(x-1)+4(x-1) 3x(x−1)+4(x−1)? What are the factors of 12x^3+12x^2+3x12x3+12x2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c^2-7512c2−75 completely? How do you factor x^6-26x^3-27x6−26x3−27? How do you factor 100x^2+180x+81100x2+180x+81? See all questions in Factoring Completely Impact of this question 1340 views around the world You can reuse this answer Creative Commons License