How do you factor #p^2 + 12p + 32#?

1 Answer
Jun 4, 2015

If #(p^2+12p+32)#
#color(white)("XXXX")#has factors #(p+a)(p+b)#

then we need to find values #a# and #b# such that
#color(white)("XXXX")##a+b = 12# and
#color(white)("XXXX")##axxb= 32#

With a bit of consideration of the possible factors of #32#
we can come up with #(4,8)#

So
#color(white)("XXXX")##p^2+12p+32 = (p+4)(p+8)#