Question

How do you factor `p^2+4p+4-q^2`?

Answer 1

`(p+2+q)(p+2-q)`

Explanation:

`p^2+4p+4-q^2`
`=(p+2)^2-q^2`
Since `a^2-b^2-(a+b)(a-b)`
Similarly the above equation `=(p+2)^2-q^2` can be written as
`(p+2+q)(p+2-q)`