How do you factor #p^2q^2-12pq+36#?

1 Answer
Apr 14, 2017

#p^2q^2-12pq+36 = (pq - 6)(pq - 6)#

Explanation:

Given: #p^2q^2-12pq+36#

This can be factored directly when we treat #pq# as a single variable that can be broken down later into two terms when their relationship is defined. To answer the question, solve for #pq#.

Looking at the expression, we see there will be two sets of brackets because of the #p^2q^2# and there will be two #-# signs due to the #+36# and the #-12#.

#p^2q^2-12pq+36 = (pq - 6)(pq - 6)#