How do you factor #s^2+10s+25#?

1 Answer
Jun 2, 2016

Answer:

#(s+5)^2#

Explanation:

Consider the structure: #(s+?)(s+?)# where the two ? may od may not be different values.

Looking at the given equation we spot that #5xx5=25# and that #5+5=10#. So these must be the values given to ?#

This gives

#(s+5)(s+5)# as both bracket contents are the same we have

#(s+5)^2#