How do you factor $s^{2} - 9$ $s^2-9$ ?

Question

How do you factor $s^{2} - 9$ $s^2-9$ ?

1 Answer

Impact of this question

2944 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-08T22:55:05

To factor $s^{2} - 9$ $s^2-9$ , you will need to use the difference of two squrares. This property tells us that $(x^{2} - y^{2})$ $(x^2-y^2)$ can be rewritten as $(x - y) (x + y)$ $(x-y)(x+y)$

In this case, $s^{2} - 9$ $s^2-9$ will become $(s - 3) (s + 3)$ $(s-3)(s+3)$ , which is the answer you are looking for.

Science

Math

Humanities

... and beyond

How do you factor $s^{2} - 9$ $s^2-9$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor s2−9 s^2-9?

1 Answer

Related questions

Impact of this question

How do you factor $s^{2} - 9$ $s^2-9$ ?