# How do you factor t^2 + 16t + 60?

Mar 26, 2018

$\left(t + 10\right) \left(t + 6\right)$

#### Explanation:

This is simple. No need to worry about.

If we have $a {x}^{2} + b x + c$ to factor, we should break $b$ to $p + q$ such that $p q = a c$.

We have,

$\textcolor{w h i t e}{\times x} {t}^{2} + 16 t + 60$

$= {t}^{2} + \left(10 + 6\right) t + 60$ [As $6 \times 10 = 60$]

$= {t}^{2} + 10 t + 6 t + 60$ [Distributive Property]

$= t \left(t + 10\right) + 6 \left(t + 10\right)$ [Grouping like terms]

$= \left(t + 10\right) \left(t + 6\right)$ [Grouping Again]

And Done. Hope this helps.