Question

How do you factor `t^2 + t +48`?

Answer 1

`t^2+t+48=(t+1/2+sqrt91/2i)(t+1/2-sqrt91/2i)`

Explanation:

`t^2+t+48`

= `t^2+2xxtxx1/2+(1/2)^2-(1/2)^2+48`

= `(t+1/2)^2+191/4`

= `(t+1/2)^2-(sqrt191/2i)^2`, where `i^2=-1`

= `(t+1/2+sqrt91/2i)(t+1/2-sqrt91/2i)`