Question

How do you factor `(t+u)^3-64`?

Answer 1

Use a³ - b³ = (a - b)(a² + ab + b²)

`a-](t+u)^3`
`b-]64`

`therefore (t+u)^3-64`
`=(t+u−64){(t+u)^2+(t+u)(64)+64^2}`