# How do you factor the expression 108g^2h - 162gh + 54h?

Oct 2, 2017

See a solution process below:

#### Explanation:

First, factor $54 h$ out of each term:

$\left(54 h \cdot 2 {g}^{2}\right) - \left(54 h \cdot 3 g\right) + \left(54 h \cdot 1\right) \implies$

$54 h \left(2 {g}^{2} - 3 g + 1\right)$

Next, factor the term within the parenthesis as:

$54 h \left(2 g - 1\right) \left(g - 1\right)$