How do you factor the expression #125b^3+27#?
1 Answer
May 22, 2018
Explanation:
#"this is a "color(blue)"sum of cubes"#
#"which factors in general as"#
#•color(white)(x)a^3+b^3=(a+b)(a^2-ab+b^2)#
#125b^3=(5b)^3rArra=5b#
#27=(3)^3rArrb=3#
#rArr125b^3+27=(5b+3)((5b)^2-(5bxx3)+3^2)#
#color(white)(raArr125b^3+27)=(5b+3)(25b^2-15b+9)#
