How do you factor the expression #133 + 208y + 64y^2#?

1 Answer
Shwetank Mauria
Mar 3, 2016

#(7+8y)(19+8y)#

Explanation:

To factorize the expression #133+208y+64y^2#, one needs to multiply the coefficient of degree two of #y# i.e.#64# and independent term #133#, which gives us #8512#.

Now find two factors of #8512#, whose product is #8512# and sum is the coefficient of #x# i.e. #208#. These would be #56# and #152#. Splitting middle term accordingly, we get

#133+208y+64y^2#

= #133+56y+152y+64y^2#

= #7(19+8y)+8y(19+8y)#

= #(7+8y)(19+8y)#

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