How do you factor the expression $16 b^{2} - 82 b - 33$ $16b^2 - 82b - 33$ ?

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How do you factor the expression $16 b^{2} - 82 b - 33$ $16b^2 - 82b - 33$ ?

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Answer 1 · 2016-03-10T18:34:10

$= (2 b - 11) (8 b + 3))$ $=(2b-11)(8b+3))$

Explanation:

$16 b^{2} - 82 b - 33$ $16b^2-82b-33$
$= 16 b^{2} - 88 + 6 b - 33$ $=16b^2-88+6b-33$
$= 8 b (2 b - 11) + 3 (2 b - 11)$ $=8b(2b-11)+3(2b-11)$
$= (2 b - 11) (8 b + 3))$ $=(2b-11)(8b+3))$

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How do you factor the expression $16 b^{2} - 82 b - 33$ $16b^2 - 82b - 33$ ?

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How do you factor the expression 16b^2 - 82b - 3316b2−82b−3316b^2 - 82b - 33?

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Explanation:

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How do you factor the expression $16 b^{2} - 82 b - 33$ $16b^2 - 82b - 33$ ?