How do you factor the expression $20x^2 + 13x + 2$ ?

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Answer 1 · 2016-04-26T21:21:06

$20x^2+13x+2=(4x+1)(5x+2)$

Use an AC method:

Find a pair of factors of $AC = 20*2 = 40$ with sum $B=13$ .

The pair $8, 5$ works in that $8xx5=40$ and $8+5 = 13$

Use this pair to split the middle term and factor by grouping:

$20x^2+13x+2$

$=20x^2+8x+5x+2$

$=(20x^2+8x)+(5x+2)$

$=4x(5x+2)+1(5x+2)$

$=(4x+1)(5x+2)$

How do you factor the expression 20x^2 + 13x + 220x^2 + 13x + 2?