How do you factor the expression $-216x^3 +1$ ?

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Answer 1 · 2016-01-03T17:02:33

First notice that you can rewrite this as

$(1-(6x)^3)$

hence using the identity

$a^3-b^3=(a-b)*(a^2+ab+b^2)$

we have that

$1-216x^3=1-(6x)^3=(1-6x)*(1+6x+36x^2)$

How do you factor the expression -216x^3 +1-216x^3 +1?