# How do you factor the expression -216x^3 +1?

First notice that you can rewrite this as

$\left(1 - {\left(6 x\right)}^{3}\right)$

hence using the identity

${a}^{3} - {b}^{3} = \left(a - b\right) \cdot \left({a}^{2} + a b + {b}^{2}\right)$

we have that

$1 - 216 {x}^{3} = 1 - {\left(6 x\right)}^{3} = \left(1 - 6 x\right) \cdot \left(1 + 6 x + 36 {x}^{2}\right)$