How do you factor the expression #2x^2+7x+1 #?

2 Answers
Mar 30, 2018

Answer:

the answer is #(-7sqrt(41))/4#

Explanation:

you can't take out so you have to use the quadratic formula. formula:#(-bsqrt(b^2-4ac))/(2a)# so plug it in wiht the numbers: #-7sqrt((7)^2-4(2)(1))/(2(2))# now solve so you'll get:#-7sqrt(49-8)/(4)# now you can simplify #41# anymore so you leave it inside. and there you go. #41# comes from #49-8#

Mar 30, 2018

Answer:

check below

Explanation:

#2x^2# + #7x# + 1
Since you can not use middle-term techniques over here.. So u can use the formula of discriminant:

myself

The equation is :

#ax^2#+#bx#+c
Here a,b,c are the coefficients of #x^2# , #x# and the constant respectively,,,