How do you factor the expression $2x³ -x² - 4x + 3$ ?

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Answer 1 · 2016-03-17T22:27:54

$2x^3-x^2-4x+3 = (x-1)(x-1)(2x+3)$

First notice that the sum of the coefficients is zero.

That is: $2-1-4+3 = 0$

So $x=1$ is a zero and $(x-1)$ a factor:

$2x^3-x^2-4x+3 = (x-1)(2x^2+x-3)$

Next notice that the sum of the coefficients of the remaining quadratic factor is also zero.

That is: $2+1-3 = 0$

So $x=1$ is a zero and $(x-1)$ a factor:

$2x^2+x-3 = (x-1)(2x+3)$

How do you factor the expression 2x³ -x² - 4x + 32x³ -x² - 4x + 3?