# How do you factor the expression 3z^2 - 13z - 30?

$= \left(x \ast b o l \mathrm{de} d \textrm{\ast} - 6\right) \left(3 x + 5\right)$
$3 {x}^{2} - 13 x - 30$
$= 3 {x}^{2} - 18 x + 5 x - 30$
$= 3 x \left(x - 6\right) + 5 x \left(x - 6\right)$
$= \left(x - 6\right) \left(3 x + 5\right)$