How do you factor the expression $49y^2 + 112y + 64$ ?

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Answer 1 · 2016-01-11T16:43:00

$49y^2+112y+64=(7y+8)^2$

$49y^2+112y+64=7^2y^2+2*7*8y+8^2=$
$=(7y)^2+2*7*8y+8^2$

Use the Square of a binomial rule

$(a+b)^2=(a^2+2ab+b^2)$

with:

$a=7y$
$b=8$

How do you factor the expression 49y^2 + 112y + 6449y^2 + 112y + 64?