How do you factor the expression 7x^2 - 28 =0?

1 Answer
Mar 13, 2018

7(x^2 -4)=0

Explanation:

Both 7 and 28 are divisible by 7 so factorizing this you would get:
7(x^2 -4)=0

After factorizing you can then proceed to solve the equation.

Dividing both sides by 7 we get x^2 -4=0 (the right hand side remains unchanged.)

We can move the 4 to the right hand side to get:
x^2 =4
The answer is thus x=±2