How do you factor the expression $81x^(4/5) - 256$ ?

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Answer 1 · 2018-05-02T15:18:38

$(9x^(2/5)-16)*(9x^(2/5)+16)$

$(sqrt(81x^(4/5))-sqrt(256))*(sqrt(81x^(4/5))+sqrt(256))$

$color(green)(sqrt(81x^(4/5))=9x^(2/5)$

$color(green)(sqrt(256)=16$

$(9x^(2/5)-16)*(9x^(2/5)+16)$

How do you factor the expression 81x^(4/5) - 256 81x^(4/5) - 256?