How do you factor the expression #r^2-4rs+4s^2#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Mia Jun 11, 2018 #r^2 - 4rs +4s^2 = (r - 2s)^2# Explanation: #r^2 -4rs + 4s^2# #" "# #=r^2 -2 (r)(2s) + (2s)^2# #" "# #=(r - 2s)^2# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1834 views around the world You can reuse this answer Creative Commons License